Provided by: git-repair_1.20151215-1.2build1_amd64 bug

NAME

       git-repair - Fix a broken git repository

SYNOPSIS

       git-repair [--force]

DESCRIPTION

       This  can  fix  a corrupt or broken git repository, which git fsck would only complain has
       problems.

       It does by deleting all corrupt objects, and retreiving all missing objects  that  it  can
       from the remotes of the repository.

       If that is not sufficient to fully recover the repository, it can also reset branches back
       to commits before the corruption happened, delete branches that are  no  longer  available
       due to the lost data, and remove any missing files from the index. It will only do this if
       run with the --force option, since that rewrites history  and  throws  out  missing  data.
       Note  that the --force option never touches tags, even if they are no longer usable due to
       missing data.

       After running this command, you will probably want to run git fsck to verify it fixed  the
       repository.  Note  that fsck may still complain about objects referenced by the reflog, or
       the stash, if they were unable to be recovered. This command does  not  try  to  clean  up
       either the reflog or the stash.

       Since  this  command  unpacks  all  packs  in  the  repository, you may want to run git gc
       afterwards.

TESTING

       git-repair is able to test itself, by making a temporary copy of the  git  reposiory  it's
       run  in,  damaging  it in random ways, and checking that it can repair it so that git fsck
       reports no problems.

       This is done using the --test parameter and associated --numtests and --retry parameters.

       Note that the testing will sometimes find repositories that  can  only  be  repaired  when
       --force  is used; this is expected. On the other hand, if it fails to recover a repository
       with --force, then the testing has found a bug!

AUTHOR

       Joey Hess <joey@kitenet.net>

       <http://git-repair.branchable.com/>

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