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NAME

       stpcpy - copy a string returning a pointer to its end

SYNOPSIS

       #define _GNU_SOURCE
       #include <string.h>

       char *stpcpy(char *dest, const char *src);

DESCRIPTION

       The  stpcpy()  function  copies the string pointed to by src (including
       the terminating '\0' character) to the array pointed to by  dest.   The
       strings  may not overlap, and the destination string dest must be large
       enough to receive the copy.

RETURN VALUE

       stpcpy() returns a pointer to the end of the string dest (that is,  the
       address of the terminating null byte) rather than the beginning.

CONFORMING TO

       This  function  is  not  part of the C or POSIX.1 standards, and is not
       customary on Unix systems, but is not a GNU invention either.   Perhaps
       it comes from MS-DOS.

EXAMPLE

       For  example,  this program uses stpcpy() to concatenate foo and bar to
       produce foobar, which it then prints.

           #include <string.h>

           int
           main (void)
           {
               char *to = buffer;
               to = stpcpy(to, "foo");
               to = stpcpy(to, "bar");
               printf("%s\n", buffer);
           }

SEE ALSO

       bcopy(3),  memccpy(3),  memcpy(3),  memmove(3),  strcpy(3),  wcpcpy(3),
       feature_test_macros(7)

COLOPHON

       This  page  is  part of release 3.01 of the Linux man-pages project.  A
       description of the project, and information about reporting  bugs,  can
       be found at http://www.kernel.org/doc/man-pages/.