Provided by: alliance_5.0-20110203-4_amd64 bug

NAME

       delbddcircuitout - deletes an output in a bdd circuit.

SYNOPSYS

       #include "bdd101.h"
       int delbddcircuitout( BddCircuit, OutputName )
         bddcircuit ∗BddCircuit;
         char       ∗OutputName;

PARAMETERS

       BddCircuit          The bdd circuit.

       OutputName          The name of the output to delete.

DESCRIPTION

       delbddcircuitout  deletes  the  output OutputName in the bdd circuit BddCircuit. If a null
       pointer is given, the default bdd circuit is used.  If the output OutputName  exists,  the
       number of external reference of the output node is decremented.

RETURN VALUE

       delbddcircuitout returns 1 if the output OutputName exist, 0 otherwise.

EXAMPLE

       #include "bdd101.h"
          bddsystem  ∗BddSystem;
          bddcircuit ∗BddCircuit;
          bddnode    ∗BddNode;
          BddSystem  = createbddsystem( 100, 1000, 100, 50000 );
          BddCircuit = createbddcircuit( "hello_world", 10, 10, BddSystem );
          ...
          addbddcircuitout( (bddcircuit ∗)0, "Out0", BddNode );
          ...
          delbddcircuitout( (bddcircuit ∗)0, "Out0" );
          destroybddsystem( (bddsystem ∗)0 );
          destroybddcircuit( (bddcircuit ∗)0 );

SEE ALSO

       bdd(1) searchbddcircuitout(3), addbddcircuitout(3).