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NAME

       stpcpy - copy a string returning a pointer to its end

SYNOPSIS

       #include <string.h>

       char *stpcpy(char *dest, const char *src);

   Feature Test Macro Requirements for glibc (see feature_test_macros(7)):

       stpcpy():
           Since glibc 2.10:
               _XOPEN_SOURCE >= 700 || _POSIX_C_SOURCE >= 200809L
           Before glibc 2.10:
               _GNU_SOURCE

DESCRIPTION

       The  stpcpy() function copies the string pointed to by src (including the terminating null
       byte ('\0')) to the array pointed to by dest.   The  strings  may  not  overlap,  and  the
       destination string dest must be large enough to receive the copy.

RETURN VALUE

       stpcpy()  returns  a  pointer  to  the end of the string dest (that is, the address of the
       terminating null byte) rather than the beginning.

CONFORMING TO

       This function was added to POSIX.1-2008. Before that, it was not part of the C or  POSIX.1
       standards,  nor  customary on UNIX systems, but was not a GNU invention either. Perhaps it
       came from MS-DOS. It is also present on the BSDs.

EXAMPLE

       For example, this program uses stpcpy() to concatenate foo  and  bar  to  produce  foobar,
       which it then prints.

           #define _GNU_SOURCE
           #include <string.h>
           #include <stdio.h>

           int
           main(void)
           {
               char buffer[20];
               char *to = buffer;

               to = stpcpy(to, "foo");
               to = stpcpy(to, "bar");
               printf("%s\n", buffer);
           }

BUGS

       This function may overrun the buffer dest.

SEE ALSO

       bcopy(3), memccpy(3), memcpy(3), memmove(3), stpncpy(3), strcpy(3), string(3), wcpcpy(3)

COLOPHON

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       project, and information about reporting bugs, can be found at  http://man7.org/linux/man-
       pages/.