Provided by: libmath-planepath-perl_125-1_all bug

NAME

       Math::PlanePath::ComplexMinus -- i-1 and other complex number bases i-r

SYNOPSIS

        use Math::PlanePath::ComplexMinus;
        my $path = Math::PlanePath::ComplexMinus->new (realpart=>1);
        my ($x, $y) = $path->n_to_xy (123);

DESCRIPTION

       This path traverses points by a complex number base i-r for given integer r.  The default is base i-1 as
       per

           Solomon I. Khmelnik "Specialized Digital Computer for Operations with Complex Numbers" (in Russian),
           Questions of Radio Electronics, volume 12, number 2, 1964.
           <http://lib.izdatelstwo.com/Papers2/s4.djvu>

           Walter Penny, "A 'Binary' System for Complex Numbers", Journal of the ACM, volume 12, number 2, April
           1965, pages 247-248.

       When continued to a power-of-2 extent this is sometimes called the "twindragon" since the shape (and
       fractal limit) limit correspond to two DragonCurve back-to-back.  But the numbering of points in the
       twindragon is not the same as here.

                 26 27       10 11                       3
                    24 25        8  9                    2
           18 19 30 31  2  3 14 15                       1
              16 17 28 29  0  1 12 13                <- Y=0
           22 23        6  7 58 59       42 43          -1
              20 21        4  5 56 57       40 41       -2
                       50 51 62 63 34 35 46 47          -3
                          48 49 60 61 32 33 44 45       -4
                       54 55       38 39                -5
                          52 53       36 37             -6

                           ^
           -5 -4 -3 -2 -1 X=0 1  2  3  4  5  6  7

       A complex integer can be represented as a set of powers,

           X+Yi = a[n]*b^n + ... + a[2]*b^2 + a[1]*b + a[0]
           base b=i-1
           digits a[n] to a[0] each = 0 or 1

           N = a[n]*2^n + ... + a[2]*2^2 + a[1]*2 + a[0]

       N is the a[i] digits as bits and X,Y is the resulting complex number.  It can be shown that this is a
       one-to-one mapping so every integer X,Y of the plane is visited once each.

       The shape of points N=0 to 2^level-1 repeats as N=2^level to 2^(level+1)-1.  For example N=0 to N=7 is
       repeated as N=8 to N=15, but starting at position X=2,Y=2 instead of the origin.  That position 2,2 is
       because b^3 = 2+2i.  There's no rotations or mirroring etc in this replication, just position offsets.

           N=0 to N=7          N=8 to N=15 repeat shape

           2   3                    10  11
               0   1                     8   9
           6   7                    14  15
               4   5                    12  13

       For b=i-1 each N=2^level point starts at X+Yi=(i-1)^level.  The powering of that b means the start
       position rotates around by +135 degrees each time and outward by a radius factor sqrt(2) each time.  So
       for example b^3 = 2+2i is followed by b^4 = -4, which is 135 degrees around and radius |b^3|=sqrt(8)
       becomes |b^4|=sqrt(16).

   Real Part
       The "realpart => $r" option gives a complex base b=i-r for a given integer r>=1.  For example "realpart
       => 2" is

           20 21 22 23 24                                               4
                 15 16 17 18 19                                         3
                       10 11 12 13 14                                   2
                              5  6  7  8  9                             1
                    45 46 47 48 49  0  1  2  3  4                   <- Y=0
                          40 41 42 43 44                               -1
                                35 36 37 38 39                         -2
                                      30 31 32 33 34                   -3
                             70 71 72 73 74 25 26 27 28 29             -4
                                   65 66 67 68 69                      -5
                                         60 61 62 63 64                -6
                                               55 56 57 58 59          -7
                                                     50 51 52 53 54    -8
                                    ^
           -8 -7 -6 -5 -4 -3 -2 -1 X=0 1  2  3  4  5  6  7  8  9 10

       N is broken into digits of base=norm=r*r+1, ie. digits 0 to r*r inclusive.  This makes horizontal runs of
       r*r+1 many points, such as N=5 to N=9 etc above.  In the default r=1 these runs are 2 long whereas for
       r=2 they're 2*2+1=5 long, or r=3 would be 3*3+1=10, etc.

       The offset back for each run like N=5 shown is the r in i-r, then the next level is (i-r)^2 = (-2r*i +
       r^2-1) so N=25 begins at Y=-2*2=-4, X=2*2-1=3.

       The successive replications tile the plane for any r, though the N values needed to rotate around and do
       so become large if norm=r*r+1 is large.

   Fractal
       The i-1 twindragon is usually conceived as taking fractional N like 0.abcde in binary and giving
       fractional complex X+iY.  The twindragon is then all the points of the complex plane reached by such
       fractional N.  This set of points can be shown to be connected and to fill a certain radius around the
       origin.

       The code here might be pressed into use for that to some finite number of bits by multiplying up to make
       an integer N

           Nint = Nfrac * 256^k
           Xfrac = Xint / 16^k
           Yfrac = Yint / 16^k

       256 is a good power because b^8=16 is a positive real and so there's no rotations to apply to the
       resulting X,Y, only a power-of-16 division (b^8)^k=16^k each.  Using b^4=-4 for a multiplier 16^k and
       divisor (-4)^k would be almost as easy too, requiring just sign changes if k odd.

FUNCTIONS

       See "FUNCTIONS" in Math::PlanePath for behaviour common to all path classes.

       "$path = Math::PlanePath::ComplexMinus->new ()"
       "$path = Math::PlanePath::ComplexMinus->new (realpart => $r)"
           Create and return a new path object.

       "($x,$y) = $path->n_to_xy ($n)"
           Return the X,Y coordinates of point number $n on the path.  Points begin at 0 and if "$n < 0" then
           the return is an empty list.

           $n should be an integer, it's unspecified yet what will be done for a fraction.

   Level Methods
       "($n_lo, $n_hi) = $path->level_to_n_range($level)"
           Return "(0, 2**$level - 1)", or with "realpart" option return "(0, $norm**$level - 1)" where
           norm=realpart^2+1.

FORMULAS

       Various formulas and pictures etc for the i-1 case can be found in the author's long mathematical write-
       up (section "Complex Base i-1")

           <http://user42.tuxfamily.org/dragon/index.html>

   X,Y to N
       A given X,Y representing X+Yi can be turned into digits of N by successive complex divisions by i-r.
       Each digit of N is a real remainder 0 to r*r inclusive from that division.

       The base formula above is

           X+Yi = a[n]*b^n + ... + a[2]*b^2 + a[1]*b + a[0]

       and want the a[0]=digit to be a real 0 to r*r inclusive.  Subtracting a[0] and dividing by b will give

           (X+Yi - digit) / (i-r)
           = - (X-digit + Y*i) * (i+r) / norm
           = (Y - (X-digit)*r)/norm
             + i * - ((X-digit) + Y*r)/norm

       which is

           Xnew = Y - (X-digit)*r)/norm
           Ynew = -((X-digit) + Y*r)/norm

       The a[0] digit must make both Xnew and Ynew parts integers.  The easiest one to calculate from is the
       imaginary part, from which require

           - ((X-digit) + Y*r) == 0 mod norm

       so

           digit = X + Y*r mod norm

       This digit value makes the real part a multiple of norm too, as can be seen from

           Xnew = Y - (X-digit)*r
                = Y - X*r - (X+Y*r)*r
                = Y - X*r - X*r + Y*r*r
                = Y*(r*r+1)
                = Y*norm

       Notice Ynew is the quotient from (X+Y*r)/norm rounded downwards (towards negative infinity).  Ie. in the
       division "X+Y*r mod norm" which calculates the digit, the quotient is Ynew and the remainder is the
       digit.

   X Axis N for Realpart 1
       For base i-1, Penney shows the N on the X axis are

           X axis N in hexadecimal uses only digits 0, 1, C, D
            = 0, 1, 12, 13, 16, 17, 28, 29, 192, 193, 204, 205, 208, ...

       Those on the positive X axis have an odd number of digits and on the X negative axis an even number of
       digits.

       To be on the X axis the imaginary parts of the base powers b^k must cancel out to leave just a real part.
       The powers repeat in an 8-long cycle

           k    b^k for b=i-1
           0        +1
           1      i -1
           2    -2i +0   \ pair cancel
           3     2i +2   /
           4        -4
           5    -4i +4
           6     8i +0   \ pair cancel
           7    -8i -8   /

       The k=0 and k=4 bits are always reals and can always be included.  Bits k=2 and k=3 have imaginary parts
       -2i and 2i which cancel out, so they can be included together.  Similarly k=6 and k=7 with 8i and -8i.
       The two blocks k=0to3 and k=4to7 differ only in a negation so the bits can be reckoned in groups of 4,
       which is hexadecimal.  Bit 1 is digit value 1 and bits 2,3 together are digit value 0xC, so adding one or
       both of those gives combinations are 0,1,0xC,0xD.

       The high hex digit determines the sign, positive or negative, of the total real part.  Bits k=0 or k=2,3
       are positive.  Bits k=4 or k=6,7 are negative, so

           N for X>0   N for X<0

             0x01..     0x1_..     even number of hex 0,1,C,D following
             0x0C..     0xC_..     "_" digit any of 0,1,C,D
             0x0D..     0xD_..

       which is equivalent to X>0 is an odd number of hex digits or X<0 is an even number.  For example
       N=28=0x1C is at X=-2 since that N is X<0 form "0x1_".

       The order of the values on the positive X axis is obtained by taking the digits in reverse order on
       alternate positions

           0,1,C,D   high digit
           D,C,1,0
           0,1,C,D
           ...
           D,C,1,0
           0,1,C,D   low digit

       For example in the following notice the first and third digit increases, but the middle digit decreases,

           X=4to7     N=0x1D0,0x1D1,0x1DC,0x1DD
           X=8to11    N=0x1C0,0x1C1,0x1CC,0x1CD
           X=12to15   N=0x110,0x111,0x11C,0x11D
           X=16to19   N=0x100,0x101,0x10C,0x10D
           X=20to23   N=0xCD0,0xCD1,0xCDC,0xCDD

       For the negative X axis it's the same if reading by increasing X, ie. upwards toward +infinity, or the
       opposite way around if reading decreasing X, ie. more negative downwards toward -infinity.

   Y Axis N for Realpart 1
       For base i-1 Penny also characterises the N values on the Y axis,

           Y axis N in base-64 uses only
             at even digits 0, 3,  4,  7, 48, 51, 52, 55
             at odd digit   0, 1, 12, 13, 16, 17, 28, 29

           = 0,3,4,7,48,51,52,55,64,67,68,71,112,115,116,119, ...

       Base-64 means taking N in 6-bit blocks.  Digit positions are counted starting from the least significant
       digit as position 0 which is even.  So the low digit can be only 0,3,4,etc, then the second digit only
       0,1,12,etc, and so on.

       This arises from (i-1)^6 = 8i which gives a repeating pattern of 6-bit blocks.  The different patterns at
       odd and even positions are since i^2 = -1.

   Boundary Length
       The length of the boundary of unit squares for the first norm^k many points, ie. N=0 to N=norm^k-1
       inclusive, is calculated in

           William J. Gilbert, "The Fractal Dimension of Sets Derived From Complex Bases", Canadian Mathematical
           Bulletin, volume 29, number 4, 1986.
           <http://www.math.uwaterloo.ca/~wgilbert/Research/GilbertFracDim.pdf>

       The boundary formula is a 3rd-order recurrence.  For the twindragon case it is

           for realpart=1
           boundary[k] = boundary[k-1] + 2*boundary[k-3]
           = 4, 6, 10, 18, 30, 50, 86, 146, 246, 418, ...  (2*A003476)

                                  4 + 2*x + 4*x^2
           generating function    ---------------
                                   1 - x - 2*x^3

       The first three boundaries are as follows.  Then the recurrence gives the next boundary[3] = 10+2*4 = 18.

            k      area     boundary[k]
           ---     ----     -----------
                                              +---+
            0     2^k = 1       4             | 0 |
                                              +---+

                                              +---+---+
            1     2^k = 2       6             | 0   1 |
                                              +---+---+

                                          +---+---+
                                          | 2   3 |
            2     2^k = 4      10         +---+   +---+
                                              | 0   1 |
                                              +---+---+

       Gilbert calculates for any i-r by taking the boundary in three parts A,B,C and showing how in the next
       replication level those boundary parts transform into multiple copies of the preceding level parts.  The
       replication is easier to visualize for a bigger "r" than for i-1 because in bigger r it's clearer how the
       A, B and C parts differ.  The length replications are

           A -> A * (2*r-1)      + C * 2*r
           B -> A * (r^2-2*r+2)  + C * (r-1)^2
           C -> B

           starting from
             A = 2*r
             B = 2
             C = 2 - 2*r

           total boundary = A+B+C

       For i-1 realpart=1 these A,B,C are already in the form of a recurrence A->A+2*C, B->A, C->B, per the
       formula above.  For other real parts a little matrix rearrangement turns the A,B,C parts into recurrence

           boundary[k] = boundary[k-1] * (2*r - 1)
                       + boundary[k-2] * (norm - 2*r)
                       + boundary[k-3] * norm

           starting from
             boundary[0] = 4               # single square cell
             boundary[1] = 2*norm + 2      # oblong of norm many cells
             boundary[2] = 2*(norm-1)*(r+2) + 4

       For example

           for realpart=2
           boundary[k] = 3*boundary[k-1] + 1*boundary[k-2] + 5*boundary[k-3]
           = 4, 12, 36, 140, 516, 1868, 6820, 24908, ...

                                        4 - 4*x^2
           generating function    ---------------------
                                  1 - 3*x - x^2 - 5*x^3

       If calculating for large k values then the matrix form can be powered up rather than repeated additions.
       (As usual for all such linear recurrences.)

OEIS

       Entries in Sloane's Online Encyclopedia of Integer Sequences related to this path include

           <http://oeis.org/A066321> (etc)

           realpart=1 (base i-1, the default)
             A066321    N on X axis, X>=0
             A271472      and in binary
             A066322    diffs (N at X=16k+4) - (N at X=16k+3)
             A066323    N on X axis, number of 1 bits
             A137426    dX/2 at N=2^(k+2)-1
                        dY at N=2^k-1   (step to next replication level)
             A256441    N on negative X axis, X<=0

             A003476    boundary length / 2
                          recurrence a(n) = a(n-1) + 2*a(n-3)
             A203175    boundary length, starting from 4
                          (believe its conjectured recurrence is true)
             A052537    boundary length part A, B or C, per Gilbert's paper

             A193239    reverse-add steps to N binary palindrome
             A193240    reverse-add trajectory of binary 110
             A193241    reverse-add trajectory of binary 10110
             A193306    reverse-subtract steps to 0 (plain-rev)
             A193307    reverse-subtract steps to 0 (rev-plain)

SEE ALSO

       Math::PlanePath, Math::PlanePath::DragonCurve, Math::PlanePath::ComplexPlus

HOME PAGE

       <http://user42.tuxfamily.org/math-planepath/index.html>

LICENSE

       Copyright 2011, 2012, 2013, 2014, 2015, 2016, 2017 Kevin Ryde

       Math-PlanePath is free software; you can redistribute it and/or modify it under the terms of the GNU
       General Public License as published by the Free Software Foundation; either version 3, or (at your
       option) any later version.

       Math-PlanePath is distributed in the hope that it will be useful, but WITHOUT ANY WARRANTY; without even
       the implied warranty of MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE.  See the GNU General Public
       License for more details.

       You should have received a copy of the GNU General Public License along with Math-PlanePath.  If not, see
       <http://www.gnu.org/licenses/>.