Provided by: libmath-planepath-perl_129-1_all bug

NAME

       Math::PlanePath::DragonCurve -- dragon curve

SYNOPSIS

        use Math::PlanePath::DragonCurve;
        my $path = Math::PlanePath::DragonCurve->new;
        my ($x, $y) = $path->n_to_xy (123);

DESCRIPTION

       This is the dragon or paper folding curve by Heighway, Harter, et al.

                        9----8    5---4               2
                        |    |    |   |
                       10--11,7---6   3---2           1
                             |            |
             17---16   13---12        0---1       <- Y=0
              |    |    |
             18-19,15-14,22-23                       -1
                   |    |    |
                  20--21,25-24                       -2
                        |
                       26---27                       -3
                             |
                --32   29---28                       -4
                   |    |
                  31---30                            -5

              ^    ^    ^    ^    ^   ^   ^
             -5   -4   -3   -2   -1  X=0  1 ...

       The curve visits "inside" X,Y points twice.  The first of these is X=-2,Y=1 which is N=7 and also N=11.
       The segments N=6,7,8 and N=10,11,12 have touched, but the path doesn't cross itself.  The doubled
       vertices are all like this, touching but not crossing and no edges repeating.

   Arms
       The curve fills a quarter of the plane and four copies mesh together perfectly when rotated by 90, 180
       and 270 degrees.  The "arms" parameter can choose 1 to 4 curve arms successively advancing.

       For example arms=4 begins as follows, with N=0,4,8,12,etc being the first arm, N=1,5,9,13 the second,
       N=2,6,10,14 the third and N=3,7,11,15 the fourth.

           arms => 4

                   20 ------ 16
                              |
                    9 ------5/12 -----  8       23
                    |         |         |        |
           17 --- 13/6 --- 0/1/2/3 --- 4/15 --- 19
            |       |         |         |
           21      10 ----- 14/7 ----- 11
                              |
                             18 ------ 22

       With four arms every X,Y point is visited twice (except the origin 0,0 where all four begin) and every
       edge between the points is traversed once.

   Level Angle
       The first step N=1 is to the right along the X axis and the path then slowly spirals anti-clockwise and
       progressively fatter.  The end of each replication is N=2^level which is at level*45 degrees around,

           N       X,Y     angle   radial dist
          ----    -----    -----   -----------
            1      1,0        0         1
            2      1,1       45       sqrt(2)
            4      0,2       90       sqrt(4)=2
            8     -2,2      135       sqrt(8)
           16     -4,0      180       sqrt(16)=4
           32     -4,-4     225       sqrt(32)
          ...

       Here's points N=0 to N=2^9=512.  "0" is the origin and "+" is N=512.  Notice it's spiralled around full-
       circle to angle 45 degrees up again, like the initial N=2.

                                           * *     * *
                                         * * *   * * *
                                         * * * * * * * * *
                                         * * * * * * * * *
                                   * *   * * * *       * *
                                 * * *   * * * *     + * *
                                 * * * * * *         * *
                                 * * * * * * *
                                 * * * * * * * *
                                     * * * * * *
                                     * * * *
                                         * * * * * * *
                                   * *   * * * * * * * *
                                 * * *   * * * * * * * *
                                 * * * * * * * * * *
                                 * * * * * * * * * * * * * * *
                                 * * * * * * * * * * * * * * * *
                                     * * * * * * * * * * * * * *
                                     * * * * * * * * * * * *
               * * * *                   * * * * * * * * * * *
               * * * * *           * *   * * * *       * * * * *
           * * * *   0 *         * * *   * * * *   * * * * * * *
           * * * *               * * * * * *       * * * * *
             * * *               * * * * * * *       * * * *
               * * * *     * *   * * * * * * * *
           * * * * * *   * * *   * * * * * * * *
           * * * * * * * * * * * * * * * * *
             * * * * * * * * * * * * * * * * *
                       * * * * *       * * * * *
                   * * * * * * *   * * * * * * *
                   * * * * *       * * * * *
                     * * * *         * * * *

       At a power of two Nlevel=2^level for N=2 or higher, the curve always goes upward from Nlevel-1 to Nlevel,
       and then goes to the left for Nlevel+1.  For example at N=16 the curve goes up N=15 to N=16, then left
       for N=16 to N=17.  Likewise at N=32, etc.  The spiral curls around ever further but the self-similar
       twist back means the Nlevel endpoint is always at this same up/left orientation.  See "Total Turn" below
       for the net direction in general.

   Level Ranges
       The X,Y extents of the path through to Nlevel=2^level can be expressed as a "length" in the direction of
       the Xlevel,Ylevel endpoint and a "width" across.

           level even, so endpoint is a straight line
           k = level/2

              +--+      <- Lmax
              |  |
              |  E      <- Lend = 2^k at Nlevel=2^level
              |
              +-----+
                    |
                 O  |   <- Lstart=0
                 |  |
                 +--+   <- Lmin

              ^     ^
           Wmin     Wmax

           Lmax = (7*2^k - 4)/6 if k even
                  (7*2^k - 2)/6 if k odd

           Lmin = - (2^k - 1)/3 if k even
                  - (2^k - 2)/3 if k odd

           Wmax = (2*2^k - 2) / 3 if k even
                  (2*2^k - 1) / 3 if k odd

           Wmin = Lmin

       For example level=2 is to Nlevel=2^2=4 and k=level/2=1 is odd so it measures as follows,

           4      <- Lmax = (7*2^1 - 2)/6 = 2
           |
           3--2
              |
           0--1   <- Lmin = -(2^1 - 2)/3 = 0

           ^  ^Wmax = (2*2^1 - 1)/3 = 1
           |
           Wmin = Lmin = 0

       Or level=4 is to Nlevel=2^4=16 and k=4/2=2 is even.  It measures as follows.  The lengthways "L" measures
       are in the direction of the N=16 endpoint and the "W" measures are across.

                 9----8    5---4        <- Wmax = (2*2^2 - 2)/3 = 2
                 |    |    |   |
                10--11,7---6   3---2
                      |            |
           16   13---12        0---1
            |    |
           15---14                      <- Wmin = -(2^2 - 1)/3 = -1

            ^                      ^Lmin = Wmin = -1
            |
            Lmax = (7*2^2 - 4)/6 = 4

       The formulas are all integer values, but the fractions 7/6, 1/3 and 2/3 show the limits as the level
       increases.  If scaled so that length Lend=2^k is reckoned as 1 unit then Lmax extends 1/6 past the end,
       Lmin and Wmin extend 1/3, and Wmax extends across 2/3.

           +--------+ --
           | -      | 1/6   total length
           || |     |          = 1/6+1+1/3 = 3/2
           || E     | --
           ||       |
           ||       |
           | \      |  1
           |  \     |
           |   --\  |
           |      \ |
           |       ||
           |  O    || --
           |  |    ||
           |  |    || 1/3
           |   ---- |
           +--------+ --
           1/3|  2/3

           total width = 1/3+2/3 = 1

   Paper Folding
       The path is called a paper folding curve because it can be generated by thinking of a long strip of paper
       folded in half repeatedly and then unfolded so each crease is a 90 degree angle.  The effect is that the
       curve repeats in successive doublings turned by 90 degrees and reversed.

       The first segment unfolds, pivoting at the "1",

                                                 2
                                            ->   |
                            unfold         /     |
                             ===>         |      |
                                                 |
           0-------1                     0-------1

       Then the same again with that L shape, pivoting at the "2", then after that pivoting at the "4", and so
       on.

                                        4
                                        |
                                        |
                                        |
                                        3--------2
                  2                              |
                  |        unfold          ^     |
                  |         ===>            \_   |
                  |                              |
           0------1                     0--------1

       It can be shown that this unfolding doesn't overlap itself but the corners may touch, such as at the
       X=-2,Y=1 etc noted above.

FUNCTIONS

       See "FUNCTIONS" in Math::PlanePath for behaviour common to all path classes.

       "$path = Math::PlanePath::DragonCurve->new ()"
       "$path = Math::PlanePath::DragonCurve->new (arms => $int)"
           Create and return a new path object.

           The optional "arms" parameter can make 1 to 4 copies of the curve, each arm successively advancing.

       "($x,$y) = $path->n_to_xy ($n)"
           Return the X,Y coordinates of point number $n on the path.  Points begin at 0 and if "$n < 0" then
           the return is an empty list.

           Fractional $n gives an X,Y position along a straight line between the integer positions.

       "$n = $path->xy_to_n ($x,$y)"
           Return the point number for coordinates "$x,$y".  If there's nothing at "$x,$y" then return "undef".

           The curve visits an "$x,$y" twice for various points (all the "inside" points).  The smaller of the
           two N values is returned.

       "@n_list = $path->xy_to_n_list ($x,$y)"
           Return a list of N point numbers for coordinates "$x,$y".

           The origin 0,0 has "arms_count()" many N since it's the starting point for each arm.  Other points
           have up to two Ns for a given "$x,$y".  If arms=4 then every "$x,$y" except the origin has exactly
           two Ns.

       "$n = $path->n_start()"
           Return 0, the first N in the path.

   Level Methods
       "($n_lo, $n_hi) = $path->level_to_n_range($level)"
           Return "(0, 2**$level)", or for multiple arms return "(0, $arms * 2**$level + ($arms-1))".

           There are 2^level segments in a curve level, so 2^level+1 points numbered from 0.  For multiple arms
           there are arms*(2^level+1) points, numbered from 0 so n_hi = arms*(2^level+1)-1.

FORMULAS

       Various formulas for coordinates, lengths and area can be found in the author's long mathematical write-
       up

           <http://user42.tuxfamily.org/dragon/index.html>

   X,Y to N
       The current code uses the "DragonMidpoint" "xy_to_n()" by rotating -45 degrees and offsetting to the
       midpoints of the four edges around the target X,Y.  The "DragonMidpoint" algorithm then gives four
       candidate N values and those which convert back to the desired X,Y in the "DragonCurve" "n_to_xy()" are
       the results for "xy_to_n_list()".

           Xmid,Ymid = X+Y, Y-X    # rotate -45 degrees
           for dx = 0 or -1
             for dy = 0 or 1
               N candidate = DragonMidpoint xy_to_n(Xmid+dx,Ymid+dy)

       Since there's at most two "DragonCurve" Ns at a given X,Y the loop can stop when two Ns are found.

       Only the "leaving" edges will convert back to the target N, so only two of the four edges actually need
       to be considered.  Is there a way to identify them?  For arm 1 and 3 the leaving edges are up,down on odd
       points (meaning sum X+Y odd) and right,left for even points (meaning sum X+Y even).  But for arm 2 and 4
       it's the other way around.  Without an easy way to determine the arm this doesn't seem to help.

   X,Y is Visited
       Whether a given X,Y is visited by the curve can be determined from one or two segments (rather then up to
       four for X,Y to N).

                   |             S midpoint Xmid = X+Y
                   |                        Ymid = Y-X
           *---T--X,Y--S---*
                   |             T midpoint Xmid-1
                   |                        Ymid+1

       Segment S is to the East of X,Y.  The arm it falls on can be determined as per "X,Y to N" in
       Math::PlanePath::DragonMidpoint.  Numbering arm(S) = 0,1,2,3 then

                                            X,Y Visited
                                            -----------
           if arms_count()==4                  yes     # whole plane
           if arm(S) < arms_count()            yes
           if arm(S)==2 and arms_count()==1    no
           if arm(T) < arms_count()            yes

       This works because when two arms touch they approach and leave by a right angle, without crossing.  So
       two opposite segments S and T identify the two possible arms coming to the X,Y point.

                  |
                  |
                   \
             ----   ----
                 \
                  |
                  |

       An arm only touches its immediate neighbour, ie. arm-1 or arm+1 mod 4.  This means if arm(S)==2 then
       arm(T) can only be 1,2,3, not 0.  So if "arms_count()" is 1 then arm(T) cannot be on the curve and no
       need to run its segment check.

       The only exception to the right-angle touching rule is at the origin X,Y = 0,0.  In that case Xmid,Ymid =
       0,0 is on the first arm and X,Y is correctly determined to be on the curve.  If S was not to the East but
       some other direction away from X,Y then this wouldn't be so.

   Turn
       At each point the curve always turns either left or right, it never goes straight ahead.  The bit above
       the lowest 1-bit in N gives the turn direction.

           N = 0b...z10000   (possibly no trailing 0s)

           z bit    Turn
           -----    ----
             0      left
             1      right

       For example N=12 is binary 0b1100, the lowest 1 bit is 0b_1__ and the bit above that is a 1, which means
       turn to the right.  Or N=18 is binary 0b10010, the lowest 1 is 0b___1_ and the bit above that is 0, so
       turn left there.

       This z bit can be picked out with some bit twiddling

           $mask = $n & -$n;          # lowest 1 bit, 000100..00
           $z = $n & ($mask << 1);    # the bit above it
           $turn = ($z == 0 ? 'left' : 'right');

       This sequence is in Knuth volume 2 "Seminumerical Algorithms" answer to section 4.5.3 question 41 and is
       called the "dragon sequence".  It's expressed there recursively as

           d(0) = 1       # unused, since first turn at N=1
           d(2N) = d(N)   # shift down looking for low 1-bit
           d(4N+1) = 0    # bit above lowest 1-bit is 0
           d(4N+3) = 1    # bit above lowest 1-bit is 1

   Next Turn
       The bits also give the turn after next by looking at the bit above the lowest 0-bit.  This works because
       011..11 + 1 = 100..00 so the bit above the lowest 0 becomes the bit above the lowest 1.

           N = 0b...w01111    (possibly no trailing 1s)

           w bit    Next Turn
           ----     ---------
             0       left
             1       right

       For example at N=12=0b1100 the lowest 0 is the least significant bit 0b___0, and above that is a 0 too,
       so at N=13 the turn is to the left.  Or for N=18=0b10010 the lowest 0 is again the least significant bit,
       but above it is a 1, so at N=19 the turn is to the right.

       This too can be found with some bit twiddling, as for example

           $mask = $n ^ ($n+1);      # low one and below 000111..11
           $w = $n & ($mask + 1);    # the bit above there
           $turn = ($w == 0 ? 'left' : 'right');

   Total Turn
       The total turn is the count of 0<->1 transitions in the runs of bits of N, which is the same as how many
       bit pairs of N (including overlaps) are different so "01" or "10".

       This can be seen from the segment replacements resulting from bits of N,

           N bits from high to low, start in "plain" state

           plain state
            0 bit -> no change
            1 bit -> count left, and go to reversed state

           reversed state
            0 bit -> count left, and go to plain state
            1 bit -> no change

       The 0 or 1 counts are from the different side a segment expands on in plain or reversed state.  Segment A
       to B expands to an "L" shape bend which is on the right in plain state, but on the left in reversed
       state.

             plain state             reverse state

             A = = = = B                    +
              \       ^              0bit  / \
               \     /               turn /   \ 1bit
           0bit \   / 1bit           left/     \
                 \ /  turn              /       v
                  +   left             A = = = = B

       In both cases a rotate of +45 degrees keeps the very first segment of the whole curve in a fixed
       direction (along the X axis), which means the south-east slope shown is no-change.  This is the 0 of
       plain or the 1 of reversed.  And the north-east slope which is the other new edge is a turn towards the
       left.

       It can be seen the "state" above is simply the previous bit, so the effect for the bits of N is to count
       a left turn at each transition from 0->1 or 1->0.  Initial "plain" state means the infinite zero bits at
       the high end of N are included.  For example N=9 is 0b1001 so three left turns for curve direction south
       to N=10 (as can be seen in the diagram above).

            1 00 1   N=9
           ^ ^  ^
           +-+--+---three transitions,
                    so three left turns for direction south

       The transitions can also be viewed as a count of how many runs of contiguous 0s or 1s, up to the highest
       1-bit.

           1 00 1   three blocks of 0s and 1s

       This can be calculated by some bit twiddling with a shift and xor to turn transitions into 1-bits which
       can then be counted, as per Jorg Arndt (fxtbook section 1.31.3.1 "The Dragon Curve").

           total turn = count_1_bits ($n ^ ($n >> 1))

       The reversing structure of the curve shows up in the total turn at each point.  The total turns for a
       block of 2^N is followed by its own reversal plus 1.  For example,

                           ------->
           N=0 to N=7    0, 1, 2, 1, 2, 3, 2, 1

           N=15 to N=8   1, 2, 3, 2, 3, 4, 3, 2    each is +1
                                      <-------

   N to dX,dY
       "n_to_dxdy()" is the "total turn" per above, or for fractional N then an offset according to the "next
       turn" above.  If using the bit twiddling operators described then the two can be calculated separately.

       The current "n_to_dxdy()" code tries to support floating point or other number types without bitwise XOR
       etc by processing bits high to low with a state table which combines the calculations for total turn and
       next turn.  The state encodes

           total turn       0 to 3
           next turn        0 or 1
           previous bit     0 or 1  (the bit above the current bit)

       The "next turn" remembers the bit above lowest 0 seen so far (or 0 initially).  The "total turn" counts
       0->1 or 1->0 transitions.  The "previous bit" shows when there's a transition, or what bit is above when
       a 0 is seen.  It also works not to have this previous bit in the state but instead pick out two bits each
       time.

       At the end of bit processing any "previous bit" in state is no longer needed and can be masked out to
       lookup the final four dx, dy, next dx, next dy.

OEIS

       The Dragon curve is in Sloane's Online Encyclopedia of Integer Sequences in many forms (and see
       "DragonMidpoint" for its forms too),

           <http://oeis.org/A014577> (etc)

           A332383   X coordinate
           A332384   Y coordinate

           A038189   turn, 0=left,1=right, bit above lowest 1, extra 0
           A089013   turn, 0=left,1=right, bit above lowest 1, extra 1
           A082410   turn, 1=left,0=right, reversing complement, extra 0
           A099545   turn, 1=left,3=right, as [odd part n] mod 4
                       so turn by 90 degrees * 1 or 3
           A034947   turn, 1=left,-1=right, Jacobi (-1/n)
           A112347   turn, 1=left,-1=right, Kronecker (-1/n), extra 0
           A121238   turn, 1=left,-1=right, -1^(n + some partitions) extra 1
           A119972   turn, n=left,-n=right
           A014577   next turn, 1=left,0=right
           A014707   next turn, 0=left,1=right
           A014709   next turn, 1=left,2=right
           A014710   next turn, 2=left,1=right
           A090678   1=same turn as previous, 0=different
           A143347   paperfolding constant, bits 0=left,1=right in decimal

       These numerous turn sequences differ only in having left or right represented as 0, 1, -1, etc, and
       possibly "extra" initial 0 or 1 at n=0 arising from the definitions and the first turn being at n=N=1.
       The "next turn" forms begin at n=0 for turn at N=1 and so are the turn at N=n+1.

           A005811   direction total turn
           A088748   direction total turn + 1
           A037834   direction total turn - 1
           A136004   direction total turn + 4
           A246960   direction 0,1,2,3 = total turn mod 4
           A173318   cumulative(total turn)
           A164910   cumulative(total turn + 1)
           A166242   2^(total turn), by double/halving
           A000975   N of new maximum total turn, binary 10101...
           A268411   direction of horizontals, 0=East, 1=West
           A043724   N of East
           A043725   N of North
           A043726   N of West
           A043727   N of South

           A088431   turn sequence run lengths
           A007400     2*runlength

           A091072   N positions of the left turns, being odd part form 4K+1
           A091067   N positions of the right turns, being odd part form 4K+3
           A255068   N positions where next turn right
           A060833   N positions where previous turn right
           A106837   N positions of consecutive turns R,R
           A106838   N positions of consecutive turns R,R,R
           A106840   N positions of consecutive turns L,L
           A106841   N positions of consecutive turns L,L,L

           A106836   N steps between right turns
           A088742   N steps between left turns
           A255070   num right turns 1 to N
           A236840   2* num right turns 1 to N
           A003460   turns N=1 to N=2^n-1 packed as bits 1=left,0=right
                       low to high, then written in octal
           A126937   coordinates coded by SquareSpiral (start N=0 and flip Y)

           A038503   num segments East  in level k
           A038504   num segments North in level k
           A038505   num segments West  in level k
           A000749   num segments South in level k

           A146559   X at N=2^k, for k>=1, being Re((i+1)^k)
           A009545   Y at N=2^k, for k>=1, being Im((i+1)^k)

           A227036   boundary length N=0 to N=2^k
                       also right boundary length to N=2^(k+1)
           A203175   left boundary length N=0 to N=2^k
                       = differences of total boundary
                       = squares on left boundary

           A003476   squares on right boundary
                       = single points N=0 to N=2^(k-1) inclusive
           A164395   single points N=0 to N=2^k-1 inclusive, for k=4 up

           A003230   area enclosed N=0 to N=2^k, for k=4 up
                      same as double points
           A003478   area enclosed by left side,
                      also area increment
           A003477   area of each blob (touching enclosed unit squares)

           A003479   join area between N=2^k replications
           A003229   join area increment,
                      also area left side extra over doubling
           A077949    same

           A289265   growth rate r = 1.695 of boundaries etc
           A272031   fractal dimension log(r)/log(sqrt(2))

           arms=4
             A165211   abs(dY), 0,1,0,1,1,0,1,0 repeating

       For reference, "dragon-like" A059125 is similar to the turn sequence A014707, but differs in having the
       "middle" values for each replication come from successive values of the sequence itself, or some such.

   A088431 and A007400
       The run lengths A088431 and A007400 are from a continued fraction expansion of an infinite sum

               1   1   1     1      1              1
           1 + - + - + -- + --- + ----- + ... + ------- + ...
               2   4   16   256   65536         2^(2^k)

       Jeffrey Shallit and independently M. Kmosek show how continued fraction terms repeated in reverse give
       rise to this sort of power sum,

           Jeffrey Shallit, "Simple Continued Fractions for Some Irrational Numbers", Journal of Number Theory,
           volume 11, 1979, pages 209-217.  <http://www.cs.uwaterloo.ca/~shallit/papers.html>,
           <http://www.cs.uwaterloo.ca/~shallit/Papers/scf.ps>

           (And which appears in Knuth "Art of Computer Programming", volume 2, section 4.5.3 exercise 41.)

   A126937
       The A126937 "SquareSpiral" numbering has the dragon curve and square spiralling with their Y axes in
       opposite directions, as shown in its a126937.pdf.  So the dragon curve turns up towards positive Y but
       the square spiral is numbered down towards negative Y (or vice versa).  "PlanePath" code for this
       starting at "$i=0" would be

             my $dragon = Math::PlanePath::DragonCurve->new;
             my $square = Math::PlanePath::SquareSpiral->new (n_start => 0);
             my ($x, $y) = $dragon->n_to_xy ($i);
             my $A126937_of_i = $square->xy_to_n ($x, -$y);

HOUSE OF GRAPHS

       House of Graphs entries for the dragon curve as a graph include

           <https://hog.grinvin.org/ViewGraphInfo.action?id=19655> etc

           19655     level=0 (1-segment path)
           32234     level=1 (2-segment path)
           286       level=2 (4-segment path)
           414       level=3 (8-segment path)
           33739     level=4
           33741     level=5
           33743     level=6
           33745     level=7
           33747     level=8

       And for just a blob (the biggest 2-connected component in its level)

           674       level=4 (4-cycle single unit square)
           25223     level=5
           33749     level=6
           33751     level=7
           33753     level=8
           34163     level=9

SEE ALSO

       Math::PlanePath, Math::PlanePath::DragonRounded, Math::PlanePath::DragonMidpoint,
       Math::PlanePath::R5DragonCurve, Math::PlanePath::TerdragonCurve

       Math::PlanePath::ComplexMinus, Math::PlanePath::ComplexPlus, Math::PlanePath::CCurve,
       Math::PlanePath::AlternatePaper

       Graph::Maker::TwindragonAreaTree

       <http://rosettacode.org/wiki/Dragon_curve>

HOME PAGE

       <http://user42.tuxfamily.org/math-planepath/index.html>

LICENSE

       Copyright 2011, 2012, 2013, 2014, 2015, 2016, 2017, 2018, 2019, 2020, 2021 Kevin Ryde

       Math-PlanePath is free software; you can redistribute it and/or modify it under the terms of the GNU
       General Public License as published by the Free Software Foundation; either version 3, or (at your
       option) any later version.

       Math-PlanePath is distributed in the hope that it will be useful, but WITHOUT ANY WARRANTY; without even
       the implied warranty of MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE.  See the GNU General Public
       License for more details.

       You should have received a copy of the GNU General Public License along with Math-PlanePath.  If not, see
       <http://www.gnu.org/licenses/>.