NAME

       FunCombine -  Combining Region and Table Filters

SYNOPSIS

       This document discusses the conventions for combining region and table filters, especially with regards
       to the comma operator.

DESCRIPTION

       Comma Conventions

       Filter specifications consist of a series of boolean expressions, separated by commas. These expressions
       can be table filters, spatial region filters, or combinations thereof. Unfortunately, common usage
       requires that the comma operator must act differently in different situations. Therefore, while its use
       is intuitive in most cases, commas can be a source of confusion.

       According to long-standing usage in IRAF, when a comma separates two table filters, it takes on the
       meaning of a boolean and. Thus:

         foo.fits[pha==1,pi==2]

       is equivalent to:

         foo.fits[pha==1 && pi==2]

       When a comma separates two spatial region filters, however, it has traditionally taken on the meaning of
       a boolean or. Thus:

         foo.fits[circle(10,10,3),ellipse(20,20,8,5)]

       is equivalent to:

         foo.fits[circle(10,10,3) ⎪⎪ ellipse(20,20,8,5)]

       (except that in the former case, each region is given a unique id in programs such as funcnts).

       Region and table filters can be combined:

         foo.fits[circle(10,10,3),pi=1:5]

       or even:

         foo.fits[pha==1&&circle(10,10,3),pi==2&&ellipse(20,20,8,5)]

       In these cases, it is not obvious whether the command should utilize an or or and operator. We therefore
       arbitrarily chose to implement the following rule:

       •   if both expressions contain a region, the operator used is or.

       •   if one (or both) expression(s) does not contain a region, the operator used is and.

       This rule handles the cases of pure regions and pure column filters properly.  It unambiguously assigns
       the boolean and to all mixed cases. Thus:

         foo.fits[circle(10,10,3),pi=1:5]

       and

         foo.fits[pi=1:5,circle(10,10,3)]

       both are equivalent to:

         foo.fits[circle(10,10,3) && pi=1:5]

       [NB: This arbitrary rule replaces the previous arbitrary rule (pre\-funtools 1.2.3) which stated:

       •   if the 2nd expression contains a region, the operator used is or.

       •   if the 2nd expression does not contain a region, the operator used is and.

       In that scenario, the or operator was implied by:

         pha==4,circle 5 5 1

       while the and operator was implied by

         circle 5 5 1,pha==4

       Experience showed that this non-commutative treatment of the comma operator was confusing and led to
       unexpected results.]

       The comma rule must be considered provisional: comments and complaints are welcome to help clarify the
       matter. Better still, we recommend that the comma operator be avoided in such cases in favor of an
       explicit boolean operator.

SEE ALSO

       See funtools(7) for a list of Funtools help pages