Provided by: manpages-dev_4.04-2_all
NAME
memmove - copy memory area
SYNOPSIS
#include <string.h> void *memmove(void *dest, const void *src, size_t n);
DESCRIPTION
The memmove() function copies n bytes from memory area src to memory area dest. The memory areas may overlap: copying takes place as though the bytes in src are first copied into a temporary array that does not overlap src or dest, and the bytes are then copied from the temporary array to dest.
RETURN VALUE
The memmove() function returns a pointer to dest.
ATTRIBUTES
For an explanation of the terms used in this section, see attributes(7). ┌──────────┬───────────────┬─────────┐ │Interface │ Attribute │ Value │ ├──────────┼───────────────┼─────────┤ │memmove() │ Thread safety │ MT-Safe │ └──────────┴───────────────┴─────────┘
CONFORMING TO
POSIX.1-2001, POSIX.1-2008, C89, C99, SVr4, 4.3BSD.
SEE ALSO
bcopy(3), memccpy(3), memcpy(3), strcpy(3), strncpy(3), wmemmove(3)
COLOPHON
This page is part of release 4.04 of the Linux man-pages project. A description of the project, information about reporting bugs, and the latest version of this page, can be found at http://www.kernel.org/doc/man-pages/.