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NAME
perlreftut - Mark's very short tutorial about references
DESCRIPTION
One of the most important new features in Perl 5 was the capability to manage complicated
data structures like multidimensional arrays and nested hashes. To enable these, Perl 5
introduced a feature called references, and using references is the key to managing
complicated, structured data in Perl. Unfortunately, there's a lot of funny syntax to
learn, and the main manual page can be hard to follow. The manual is quite complete, and
sometimes people find that a problem, because it can be hard to tell what is important and
what isn't.
Fortunately, you only need to know 10% of what's in the main page to get 90% of the
benefit. This page will show you that 10%.
Who Needs Complicated Data Structures?
One problem that comes up all the time is needing a hash whose values are lists. Perl has
hashes, of course, but the values have to be scalars; they can't be lists.
Why would you want a hash of lists? Let's take a simple example: You have a file of city
and country names, like this:
Chicago, USA
Frankfurt, Germany
Berlin, Germany
Washington, USA
Helsinki, Finland
New York, USA
and you want to produce an output like this, with each country mentioned once, and then an
alphabetical list of the cities in that country:
Finland: Helsinki.
Germany: Berlin, Frankfurt.
USA: Chicago, New York, Washington.
The natural way to do this is to have a hash whose keys are country names. Associated
with each country name key is a list of the cities in that country. Each time you read a
line of input, split it into a country and a city, look up the list of cities already
known to be in that country, and append the new city to the list. When you're done
reading the input, iterate over the hash as usual, sorting each list of cities before you
print it out.
If hash values couldn't be lists, you lose. You'd probably have to combine all the cities
into a single string somehow, and then when time came to write the output, you'd have to
break the string into a list, sort the list, and turn it back into a string. This is
messy and error-prone. And it's frustrating, because Perl already has perfectly good
lists that would solve the problem if only you could use them.
The Solution
By the time Perl 5 rolled around, we were already stuck with this design: Hash values must
be scalars. The solution to this is references.
A reference is a scalar value that refers to an entire array or an entire hash (or to just
about anything else). Names are one kind of reference that you're already familiar with.
Each human being is a messy, inconvenient collection of cells. But to refer to a
particular human, for instance the first computer programmer, it isn't necessary to
describe each of their cells; all you need is the easy, convenient scalar string "Ada
Lovelace".
References in Perl are like names for arrays and hashes. They're Perl's private, internal
names, so you can be sure they're unambiguous. Unlike a human name, a reference only
refers to one thing, and you always know what it refers to. If you have a reference to an
array, you can recover the entire array from it. If you have a reference to a hash, you
can recover the entire hash. But the reference is still an easy, compact scalar value.
You can't have a hash whose values are arrays; hash values can only be scalars. We're
stuck with that. But a single reference can refer to an entire array, and references are
scalars, so you can have a hash of references to arrays, and it'll act a lot like a hash
of arrays, and it'll be just as useful as a hash of arrays.
We'll come back to this city-country problem later, after we've seen some syntax for
managing references.
Syntax
There are just two ways to make a reference, and just two ways to use it once you have it.
Making References
Make Rule 1
If you put a "\" in front of a variable, you get a reference to that variable.
$aref = \@array; # $aref now holds a reference to @array
$href = \%hash; # $href now holds a reference to %hash
Once the reference is stored in a variable like $aref or $href, you can copy it or store
it just the same as any other scalar value:
$xy = $aref; # $xy now holds a reference to @array
$p[3] = $href; # $p[3] now holds a reference to %hash
$z = $p[3]; # $z now holds a reference to %hash
These examples show how to make references to variables with names. Sometimes you want to
make an array or a hash that doesn't have a name. This is analogous to the way you like
to be able to use the string "\n" or the number 80 without having to store it in a named
variable first.
Make Rule 2
"[ ITEMS ]" makes a new, anonymous array, and returns a reference to that array. "{ ITEMS
}" makes a new, anonymous hash, and returns a reference to that hash.
$aref = [ 1, "foo", undef, 13 ];
# $aref now holds a reference to an array
$href = { APR => 4, AUG => 8 };
# $href now holds a reference to a hash
The references you get from rule 2 are the same kind of references that you get from rule
1:
# This:
$aref = [ 1, 2, 3 ];
# Does the same as this:
@array = (1, 2, 3);
$aref = \@array;
The first line is an abbreviation for the following two lines, except that it doesn't
create the superfluous array variable @array.
If you write just "[]", you get a new, empty anonymous array. If you write just "{}", you
get a new, empty anonymous hash.
Using References
What can you do with a reference once you have it? It's a scalar value, and we've seen
that you can store it as a scalar and get it back again just like any scalar. There are
just two more ways to use it:
Use Rule 1
You can always use an array reference, in curly braces, in place of the name of an array.
For example, "@{$aref}" instead of @array.
Here are some examples of that:
Arrays:
@a @{$aref} An array
reverse @a reverse @{$aref} Reverse the array
$a[3] ${$aref}[3] An element of the array
$a[3] = 17; ${$aref}[3] = 17 Assigning an element
On each line are two expressions that do the same thing. The left-hand versions operate
on the array @a. The right-hand versions operate on the array that is referred to by
$aref. Once they find the array they're operating on, both versions do the same things to
the arrays.
Using a hash reference is exactly the same:
%h %{$href} A hash
keys %h keys %{$href} Get the keys from the hash
$h{'red'} ${$href}{'red'} An element of the hash
$h{'red'} = 17 ${$href}{'red'} = 17 Assigning an element
Whatever you want to do with a reference, Use Rule 1 tells you how to do it. You just
write the Perl code that you would have written for doing the same thing to a regular
array or hash, and then replace the array or hash name with "{$reference}". "How do I
loop over an array when all I have is a reference?" Well, to loop over an array, you
would write
for my $element (@array) {
...
}
so replace the array name, @array, with the reference:
for my $element (@{$aref}) {
...
}
"How do I print out the contents of a hash when all I have is a reference?" First write
the code for printing out a hash:
for my $key (keys %hash) {
print "$key => $hash{$key}\n";
}
And then replace the hash name with the reference:
for my $key (keys %{$href}) {
print "$key => ${$href}{$key}\n";
}
Use Rule 2
Use Rule 1 is all you really need, because it tells you how to do absolutely everything
you ever need to do with references. But the most common thing to do with an array or a
hash is to extract a single element, and the Use Rule 1 notation is cumbersome. So there
is an abbreviation.
"${$aref}[3]" is too hard to read, so you can write "$aref->[3]" instead.
"${$href}{red}" is too hard to read, so you can write "$href->{red}" instead.
If $aref holds a reference to an array, then "$aref->[3]" is the fourth element of the
array. Don't confuse this with $aref[3], which is the fourth element of a totally
different array, one deceptively named @aref. $aref and @aref are unrelated the same way
that $item and @item are.
Similarly, "$href->{'red'}" is part of the hash referred to by the scalar variable $href,
perhaps even one with no name. $href{'red'} is part of the deceptively named %href hash.
It's easy to forget to leave out the "->", and if you do, you'll get bizarre results when
your program gets array and hash elements out of totally unexpected hashes and arrays that
weren't the ones you wanted to use.
An Example
Let's see a quick example of how all this is useful.
First, remember that "[1, 2, 3]" makes an anonymous array containing "(1, 2, 3)", and
gives you a reference to that array.
Now think about
@a = ( [1, 2, 3],
[4, 5, 6],
[7, 8, 9]
);
@a is an array with three elements, and each one is a reference to another array.
$a[1] is one of these references. It refers to an array, the array containing "(4, 5,
6)", and because it is a reference to an array, Use Rule 2 says that we can write
"$a[1]->[2]" to get the third element from that array. "$a[1]->[2]" is the 6. Similarly,
"$a[0]->[1]" is the 2. What we have here is like a two-dimensional array; you can write
"$a[ROW]->[COLUMN]" to get or set the element in any row and any column of the array.
The notation still looks a little cumbersome, so there's one more abbreviation:
Arrow Rule
In between two subscripts, the arrow is optional.
Instead of "$a[1]->[2]", we can write "$a[1][2]"; it means the same thing. Instead of
"$a[0]->[1] = 23", we can write "$a[0][1] = 23"; it means the same thing.
Now it really looks like two-dimensional arrays!
You can see why the arrows are important. Without them, we would have had to write
"${$a[1]}[2]" instead of "$a[1][2]". For three-dimensional arrays, they let us write
"$x[2][3][5]" instead of the unreadable "${${$x[2]}[3]}[5]".
Solution
Here's the answer to the problem I posed earlier, of reformatting a file of city and
country names.
1 my %table;
2 while (<>) {
3 chomp;
4 my ($city, $country) = split /, /;
5 $table{$country} = [] unless exists $table{$country};
6 push @{$table{$country}}, $city;
7 }
8 for my $country (sort keys %table) {
9 print "$country: ";
10 my @cities = @{$table{$country}};
11 print join ', ', sort @cities;
12 print ".\n";
13 }
The program has two pieces: Lines 2-7 read the input and build a data structure, and lines
8-13 analyze the data and print out the report. We're going to have a hash, %table, whose
keys are country names, and whose values are references to arrays of city names. The data
structure will look like this:
%table
+-------+---+
| | | +-----------+--------+
|Germany| *---->| Frankfurt | Berlin |
| | | +-----------+--------+
+-------+---+
| | | +----------+
|Finland| *---->| Helsinki |
| | | +----------+
+-------+---+
| | | +---------+------------+----------+
| USA | *---->| Chicago | Washington | New York |
| | | +---------+------------+----------+
+-------+---+
We'll look at output first. Supposing we already have this structure, how do we print it
out?
8 for my $country (sort keys %table) {
9 print "$country: ";
10 my @cities = @{$table{$country}};
11 print join ', ', sort @cities;
12 print ".\n";
13 }
%table is an ordinary hash, and we get a list of keys from it, sort the keys, and loop
over the keys as usual. The only use of references is in line 10. $table{$country} looks
up the key $country in the hash and gets the value, which is a reference to an array of
cities in that country. Use Rule 1 says that we can recover the array by saying
"@{$table{$country}}". Line 10 is just like
@cities = @array;
except that the name "array" has been replaced by the reference "{$table{$country}}". The
"@" tells Perl to get the entire array. Having gotten the list of cities, we sort it,
join it, and print it out as usual.
Lines 2-7 are responsible for building the structure in the first place. Here they are
again:
2 while (<>) {
3 chomp;
4 my ($city, $country) = split /, /;
5 $table{$country} = [] unless exists $table{$country};
6 push @{$table{$country}}, $city;
7 }
Lines 2-4 acquire a city and country name. Line 5 looks to see if the country is already
present as a key in the hash. If it's not, the program uses the "[]" notation (Make Rule
2) to manufacture a new, empty anonymous array of cities, and installs a reference to it
into the hash under the appropriate key.
Line 6 installs the city name into the appropriate array. $table{$country} now holds a
reference to the array of cities seen in that country so far. Line 6 is exactly like
push @array, $city;
except that the name "array" has been replaced by the reference "{$table{$country}}". The
"push" adds a city name to the end of the referred-to array.
There's one fine point I skipped. Line 5 is unnecessary, and we can get rid of it.
2 while (<>) {
3 chomp;
4 my ($city, $country) = split /, /;
5 #### $table{$country} = [] unless exists $table{$country};
6 push @{$table{$country}}, $city;
7 }
If there's already an entry in %table for the current $country, then nothing is different.
Line 6 will locate the value in $table{$country}, which is a reference to an array, and
push $city into the array. But what does it do when $country holds a key, say "Greece",
that is not yet in %table?
This is Perl, so it does the exact right thing. It sees that you want to push "Athens"
onto an array that doesn't exist, so it helpfully makes a new, empty, anonymous array for
you, installs it into %table, and then pushes "Athens" onto it. This is called
autovivification--bringing things to life automatically. Perl saw that the key wasn't in
the hash, so it created a new hash entry automatically. Perl saw that you wanted to use
the hash value as an array, so it created a new empty array and installed a reference to
it in the hash automatically. And as usual, Perl made the array one element longer to
hold the new city name.
The Rest
I promised to give you 90% of the benefit with 10% of the details, and that means I left
out 90% of the details. Now that you have an overview of the important parts, it should
be easier to read the perlref manual page, which discusses 100% of the details.
Some of the highlights of perlref:
• You can make references to anything, including scalars, functions, and other
references.
• In Use Rule 1, you can omit the curly brackets whenever the thing inside them is an
atomic scalar variable like $aref. For example, @$aref is the same as "@{$aref}", and
$$aref[1] is the same as "${$aref}[1]". If you're just starting out, you may want to
adopt the habit of always including the curly brackets.
• This doesn't copy the underlying array:
$aref2 = $aref1;
You get two references to the same array. If you modify "$aref1->[23]" and then look
at "$aref2->[23]" you'll see the change.
To copy the array, use
$aref2 = [@{$aref1}];
This uses "[...]" notation to create a new anonymous array, and $aref2 is assigned a
reference to the new array. The new array is initialized with the contents of the
array referred to by $aref1.
Similarly, to copy an anonymous hash, you can use
$href2 = {%{$href1}};
• To see if a variable contains a reference, use the "ref" function. It returns true if
its argument is a reference. Actually it's a little better than that: It returns
"HASH" for hash references and "ARRAY" for array references.
• If you try to use a reference like a string, you get strings like
ARRAY(0x80f5dec) or HASH(0x826afc0)
If you ever see a string that looks like this, you'll know you printed out a reference
by mistake.
A side effect of this representation is that you can use "eq" to see if two references
refer to the same thing. (But you should usually use "==" instead because it's much
faster.)
• You can use a string as if it were a reference. If you use the string "foo" as an
array reference, it's taken to be a reference to the array @foo. This is called a
symbolic reference. The declaration "use strict 'refs'" disables this feature, which
can cause all sorts of trouble if you use it by accident.
You might prefer to go on to perllol instead of perlref; it discusses lists of lists and
multidimensional arrays in detail. After that, you should move on to perldsc; it's a Data
Structure Cookbook that shows recipes for using and printing out arrays of hashes, hashes
of arrays, and other kinds of data.
Summary
Everyone needs compound data structures, and in Perl the way you get them is with
references. There are four important rules for managing references: Two for making
references and two for using them. Once you know these rules you can do most of the
important things you need to do with references.
Credits
Author: Mark Jason Dominus, Plover Systems ("mjd-perl-ref+@plover.com")
This article originally appeared in The Perl Journal ( <http://www.tpj.com/> ) volume 3,
#2. Reprinted with permission.
The original title was Understand References Today.
Distribution Conditions
Copyright 1998 The Perl Journal.
This documentation is free; you can redistribute it and/or modify it under the same terms
as Perl itself.
Irrespective of its distribution, all code examples in these files are hereby placed into
the public domain. You are permitted and encouraged to use this code in your own programs
for fun or for profit as you see fit. A simple comment in the code giving credit would be
courteous but is not required.